Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings.
For example,
Given [[0, 30],[5, 10],[15, 20]],
return false.
Thoughts
interval问题先按start时间排序. 再一个个检查是否有冲突即可.
Code
/**
* Definition for an interval.
* public class Interval {
* int start;
* int end;
* Interval() { start = 0; end = 0; }
* Interval(int s, int e) { start = s; end = e; }
* }
*/
class Solution {
public boolean canAttendMeetings(Interval[] intervals) {
Arrays.sort(intervals, (a, b) -> a.start - b.start);
for (int i = 1; i < intervals.length; i++) {
if (intervals[i].start < intervals[i - 1].end) {
return false;
}
}
return true;
}
}