Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.
An example is the root-to-leaf path 1->2->3 which represents the number 123.
Find the total sum of all root-to-leaf numbers.
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int res = 0;
int sumNumbers(TreeNode* root) {
dfs(root, 0);
return res;
}
void dfs(TreeNode *cur, int psum) {
if (cur == NULL) return;
psum = psum * 10 + cur->val;
if (cur->left == NULL && cur->right == NULL) res += psum;
dfs(cur->left, psum);
dfs(cur->right, psum);
}
};
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int sumNumbers(TreeNode* root) {
stack<TreeNode*> s;
int psum = 0;
TreeNode *pre = NULL;
int res = 0;
const auto push_left = [&](TreeNode *cur) {
while (cur != NULL) {
s.push(cur);
psum = psum * 10 + cur->val;
cur = cur->left;
}
pre = NULL;
};
push_left(root);
while (!s.empty()) {
const auto cur = s.top();
if (cur->right != pre) {
push_left(cur->right);
continue;
}
if (cur->left == NULL && cur->right == NULL) {
res += psum;
}
psum -= cur->val;
psum /= 10;
s.pop();
pre = cur;
}
return res;
}
};