1647. Minimum Deletions to Make Character Frequencies Unique
https://leetcode.com/problems/minimum-deletions-to-make-character-frequencies-unique/
A string s
is called good if there are no two different characters in s
that have the same frequency.
Given a string s
, return the minimum number of characters you need to delete to make s
good.
The frequency of a character in a string is the number of times it appears in the string. For example, in the string "aab"
, the frequency of 'a'
is 2
, while the frequency of 'b'
is 1
.
Example 1:
Input: s = "aab"
Output: 0
Explanation: s is already good.
Example 2:
Input: s = "aaabbbcc"
Output: 2
Explanation: You can delete two 'b's resulting in the good string "aaabcc".
Another way it to delete one 'b' and one 'c' resulting in the good string "aaabbc".
Example 3:
Input: s = "ceabaacb"
Output: 2
Explanation: You can delete both 'c's resulting in the good string "eabaab".
Note that we only care about characters that are still in the string at the end (i.e. frequency of 0 is ignored).
Constraints:
1 <= s.length <= 10**5
s
contains only lowercase English letters.
由小写字母组成的字符串,问最少去掉多少字符能使得字符串中每个字符出现频次是唯一的。贪心地将每个字符出现的频次不断减一,直到是唯一频次。
class Solution:
def minDeletions(self, s: str) -> int:
cnt, used, res = collections.Counter(s), set(), 0
for _, f in cnt.items():
while f > 0 and f in used:
res += 1
f -= 1
used.add(f)
return res
Last updated
Was this helpful?