1344. Angle Between Hands of a Clock

https://leetcode.com/problems/angle-between-hands-of-a-clock/

Given two numbers, hour and minutes. Return the smaller angle (in degrees) formed between the hour and the minute hand.

Example 1:

Input: hour = 12, minutes = 30
Output: 165

Example 2:

Input: hour = 3, minutes = 30
Output: 75

Example 3:

Input: hour = 3, minutes = 15
Output: 7.5

Example 4:

Input: hour = 4, minutes = 50
Output: 155

Example 5:

Input: hour = 12, minutes = 0
Output: 0

Constraints:

• 1 <= hour <= 12

• 0 <= minutes <= 59

• Answers within 10^-5 of the actual value will be accepted as correct.

问给定时间在时钟上时针和分针相差的角度（小的那个）是多少。时针把360°分成了12份格子，分针分成了60份，且时钟会随着当前分钟数在相关格子内移动对应长度。

class Solution:
    def angleClock(self, hour: int, minutes: int) -> float:
        abd = abs(hour * 30 + minutes / 60 * 30 - minutes * 6)
        return min(360 - abd, abd)