Input: 1->2->6->3->4->5->6, val = 6
Output: 1->2->3->4->5
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def removeElements(self, head: ListNode, val: int) -> ListNode:
dummy, cur = ListNode(), head
add = dummy
while cur:
if cur.val != val:
add.next = cur
add = add.next
cur = cur.next
add.next = None
return dummy.next
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* removeElements(ListNode* head, int val) {
ListNode dummy_node(-1);
auto dummy = &dummy_node, node = dummy;
dummy->next = head;
while (node != NULL && node->next != NULL) {
if (node->next->val == val) {
node->next = node->next->next;
} else {
node = node->next;
}
}
return dummy->next;
}
};