/* * @lc app=leetcode id=239 lang=cpp * * [239] Sliding Window Maximum * * https://leetcode.com/problems/sliding-window-maximum/description/ * * algorithms * Hard (39.10%) * Likes: 2011 * Dislikes: 118 * Total Accepted: 180.1K * Total Submissions: 460.2K * Testcase Example: '[1,3,-1,-3,5,3,6,7]\n3' * * Given an array nums, there is a sliding window of size k which is moving * from the very left of the array to the very right. You can only see the k * numbers in the window. Each time the sliding window moves right by one * position. Return the max sliding window. * * Example: * * * Input: nums = [1,3,-1,-3,5,3,6,7], and k = 3 * Output: [3,3,5,5,6,7] * Explanation: * * Window position Max * --------------- ----- * [1 3 -1] -3 5 3 6 7 3 * 1 [3 -1 -3] 5 3 6 7 3 * 1 3 [-1 -3 5] 3 6 7 5 * 1 3 -1 [-3 5 3] 6 7 5 * 1 3 -1 -3 [5 3 6] 7 6 * 1 3 -1 -3 5 [3 6 7] 7 * * * Note: * You may assume k is always valid, 1 ≤ k ≤ input array's size for non-empty * array. * * Follow up: * Could you solve it in linear time? */classSolution {public:vector<int> maxSlidingWindow(vector<int>& nums,int k) { deque<int> q; vector<int> res;for (int i =0; i <nums.size(); ++i) {while (!q.empty() &&nums[i] >q.back()) q.pop_back();q.push_back(nums[i]);constint f = i - k +1;if (f <0) continue;res.push_back(q.front());if (nums[f] ==q.front()) q.pop_front(); }return res; }};